如何为std :: array的列表初始化构造函数编写包装器? [英] How to write a wrapper for std::array's list initialization constructor?
问题描述
我正在写一个包装程序,出于这个问题的目的,它只包装了SequenceContainer( http://en.cppreference.com/w/cpp/concept/SequenceContainer ),并复制包装容器提供的SequenceContainer概念的所有功能。
I’m writing a wrapper that, for the purpose of this question, does nothing but wraps a SequenceContainer ( http://en.cppreference.com/w/cpp/concept/SequenceContainer ) and reproduces all functionality of the SequenceContainer concept the wrapped container offers.
我写这样一个包装的尝试看起来像这样:
My attempt to write such a wrapper looks like this:
template<class Container>
class SequenceContainerWrapper
{
Container cont;
public:
using value_type = typename Container::value_type;
using reference = typename Container::reference;
using size_type = typename Container::size_type;
SequenceContainerWrapper(initializer_list<value_type> init) : cont(init) {}
reference operator[] (size_type n) {return cont[n];}
// lots of other code that does nothing but wrapping
};
是的,例如–我可以将其与 std ::一起使用:向量
。下面的代码可以按预期方式编译和运行( http://ideone.com/sYeIeJ ):
And yes – I can use it, for example, with std::vector
. The below code compiles and works as expected ( http://ideone.com/sYeIeJ ):
int main()
{
SequenceContainerWrapper<vector<int>> vec({1,2,3,4});
cout << vec[2] << '\n';
}
但是,此构造函数不适用于 std :: array
。此代码段无法编译( http://ideone.com/5nZhar ):
However, this constructor won’t work with std::array
. This snippet does not compile ( http://ideone.com/5nZhar ):
int main()
{
SequenceContainerWrapper<array<int, 4>> arr({1,2,3,4});
cout << arr[2] << '\n';
}
这是因为( http://en.cppreference.com/w/cpp/concept/SequenceContainer#cite_note-1 ):
std :: array支持通过括号初始化列表进行赋值,但不支持通过std :: initializer_list进行赋值
std::array supports assignment from a braced-init-list, but not from an std::initializer_list
所以我如何在包装器中重现用括号括起来的 std :: array
的可能性, init-list ,而不会牺牲包装器的通用性,并引入了一些解决方案,这些解决方案将削弱包装器的兼容性,例如 std :: vector
?
So how can I reproduce in my wrapper the possibility to initialize an std::array
with a braced-init-list without sacrificing the genericness of my wrapper and introducing solutions that will cripple the wrapper’s compatibility with e.g. std::vector
?
推荐答案
而不是使用:
SequenceContainerWrapper(initializer_list<value_type> init) : cont(init) {}
您可以使用:
SequenceContainerWrapper(Container init) : cont(std::move(init)) {}
请参见 href = http://ideone.com/MzRQGC rel = nofollow noreferrer> http://ideone.com/MzRQGC 。
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