根据值将数组分成几组 [英] Breaking an array into groups based on values

问题描述

我正在使用PHP，根据一组值将一个数组分解为多个数组。这些组基于介于1到5之间的值。但是这是困难的部分...

Using PHP, I'm trying to break an array up into multiple arrays based on groups of values. The groups are based on the values being between 1 and 5. But here's the hard part...

我需要遍历数组并放入第一组值在自己的数组中是1到5之间，然后在自己的数组中是下一个在1到5之间的值，依此类推。

I need to loop through the array and put the first set of values that are between 1 and 5 in their own array, then the next set of values that are between 1 and 5 in their own array, and so on.

但是每个组不会总是包含1,2,3,4,5。某些组可能是随机的。

But each group WON'T always include 1,2,3,4,5. Some groups could be random.

示例：

1,1,2,2,3,4， 5-这将是一个组

1,1,2,2,3,4,5 - this would be a group

1,2,3,4,4,4-这将是一个组

1,2,3,4,4,4 - this would be a group

1,2,3,3,5-这将是一个组

1,2,3,3,5 - this would be a group

2,2,3,3,5-这将是一个组

2,2,3,3,5 - this would be a group

所以我不能只测试特定数字。

So I can't just test for specific numbers.

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => 4
    [4] => 5
    [5] => 1
    [6] => 2
    [7] => 3
    [8] => 4
    [9] => 4
    [10] => 1
    [11] => 1
    [12] => 3
    [13] => 4
    [14] => 5
)

有任何想法吗？

推荐答案

我只是检查当前值是否大于先前值，如果是， ，开始一个新组。

I would just check if the current value is larger than the previous value, and if yes, begin a new group.

$groups = array();
$groupcount = 1;

foreach( $array as $key=>$value )
{
    if( $key > 0 )  // there's no "previous value" for the first entry
    {
        if( $array[$key] < $array[$key-1] )
        {
            $groupcount = $groupcount + 1;
        }
    }

    $group[groupcount][] = $value;
}

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