从文本文件读取并存储到数组C ++ [英] Read from a text file and storing to an array C++

问题描述

我有一个程序可以从文本文件（sortarraysin.txt）中读取值，并将这些值存储到数组中。但是，当我尝试将阵列打印到控制台时，我的输出不会显示文本文件中的数字。我的文本文件和程序如下所示。

I have a program that reads values from a text file(sortarraysin.txt) and stores those values into an array. However when I try to print the array to the console my output does not display the numbers from the text file. My text file and program are shown below.

文本文件：

45 59 302 48 51 3 1 23

程序：

int array[8];
int i = 0;
string inFileName, getcontent;
cout << "Enter input file name -> ";
cin >> inFileName;
fstream inFileStr(inFileName.c_str(), ios::in);
if(inFileStr.fail()){
    cerr << "Unable to open " << inFileName << endl;
    exit(-1);
}
if(inFileStr.is_open()){
    while(!inFileStr.eof()){
        getline(inFileStr, getcontent);
        cout << getcontent << endl;
        array[i++] << atoi(getcontent.c_str());
        for(i=0;i<=8;i++){
        cout << array[i] << " ";
        }
    }
}

输出：

Enter input file name -> sortarraysin.txt 
45 59 302 48 51 3 1 23
-2145069216 1 -13232 0 -2145069216 1 -12816 0 -13136

为什么我的数组值打印这些数字而不是文本文件中的值？

Why are my array values printing these numbers instead of the values from the text file?

推荐答案

int value;
int i = 0;
while(inFileStr >> value)
{ 
   myArray[i] = value;
   i++;
}

如果您遵循我的指示，则无需使用getline，并且不需要将字符串转换为整数。记住更少的代码会更快。.

you don't need to use getline if you follow my instruction, and you will not need to convert string to integer. Remember less code is faster..

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