将对象数组重新排序为嵌套对象 [英] Reordering array of objects into nested objects

问题描述

如何重新排列对象数组

[ {"2007": rank, "2008": rank, "Class": "label 1"}, 
  {"2007": rank, "2008": rank, "Class": "label 2"}, ... ]

放入嵌套对象，例如：

 {"2007": 
      {"label 1": rank, "label 2": rank}, 
 "2008": 
      {"label 1": rank, "label 2": rank}, ...}

推荐答案

要求是按 Class 来转置表和索引：

It seems that your requirement is to transpose the table and index by Class:

• 调用输入表格


• 每年调用数组行中的每个元素


• 是至少一行中的键，除了键 Class
  
  
  
  • make year 输出中的键，映射到对象：
    
    
    
    • output [year] 是某行中 Class 的值 class v提示：
      
      
      
      • output [year] [class] = input.find（ Class ，class）[year]
      
      
      • call the input "table"
      • call every element of the array "row"
      • for every year that is a key in at least one row, except the key Class
        • make year a key in output, mapping to the object:
          • each key in output[year] is the value class of Class in some row, mapping to the value:
            • output[year][class] = input.find("Class",class)[year]

            这是一种可能的实现方式：

            This is one possible implementation:

             var input = [ {"2007": rank, "2008": rank, "Class": "label 1"}, 
                           {"2007": rank, "2008": rank, "Class": "label 2"} ]
             //////////
             var yr, i;
             var output = {};
             for(i=0; i<input.length; i++){
               var row = input[i];
               for(yr in row){
                 output[yr] = output[yr] || {};
                 output[yr][row.Class] = row[yr];
               }
             }
             //////////////
             return output;
            

            测试： http://jsfiddle.net/aT5YG/1

            如果多个行具有相同的 Class ，后面的行将覆盖前面的行。如果nput呈锯齿状，则输出将呈锯齿状。

            If multiple rows have the same Class, the later rows overwrite the previous rows. If the nput was jagged, the output will be jagged.

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