C ++如何在不同位置用新字符串填充字符串的静态数组？ [英] C++ How to populate a static array of strings with new strings in different locations?
问题描述
说我明白了
char* MapIds[5000] = { "Northeast Asia","Hanyang","Pusan","Pyongyang","Shanghai","Beijing","Hong Kong", /*...5000 values etc../* };
我尝试过
strcpy(MapIds[0], "gfggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg");
但是它崩溃了
我该怎么办不断更改它们而不会弄乱其他元素中的字符串。
How Do I keep changing them around without messing up the strings in other elements.
我不想使用std :: string或vector导致疯狂的缓慢编译时间。
I dont want to use std::string or vector those cause crazy slow compile times.
推荐答案
因为您尝试将其复制为文字字符串（东北亚 ）。
Because you try to copy into a literal string ("Northeast Asia").
在C ++中，文字字符串实际上是字符的 恒定数组，任何尝试修改此类数组的尝试都会导致未定义的行为（有时可能会表示为崩溃）。
In C++ a literal string is really a constant array of characters, any attempt to modify such an array will lead to undefined behavior (which can sometimes express themselves as crashes).
如果您想创建 MapIds [0 ] point 指向一个新字符串，然后只需使用赋值即可：
If you want to make MapIds[0] point to a new string, then you simply use assignment:
MapIds[0] = "gfggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg";
因为文字字符串是恒定的字符数组，所以C ++并没有真正允许您使用 char * 指向它们，您必须使用 const char * ：
Because literal strings are constant arrays of characters, C++ doesn't really allow you to have a char* to point to them, you must use const char*:
const char* MapIds[] = { ... };
但是，更好的解决方案是不使用C样式字符串和 char 指针（是否使用 const ），但仅使用 std :: string ：
However, a much better solution is to not use C-style strings and char pointers (const or not) at all, but only use std::string:
std::string MapIds[] = { ... };
然后，您可以使用上面所示的简单赋值来修改数组本身中的字符串。
Then you can modify the strings in the array itself, using plain assignment as shown above.
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