在初始化时定义位大小？ [英] Define bitset size at initialization?

问题描述

我想在C ++中做一个位。我做了一些研究。我发现的所有示例都是这样的：

I want to make a bitset in C++. I did a bit of research. All examples I found where like this:

bitset<6> myBitset;
// do something with it

但是我不知道位的大小当我在类中定义变量时：

But I don't know the size of the bitset when I define the variable in my class:

#include <bitset>
class Test
{
public:
     std::bitset *myBitset;
}

这不会编译...

像这样的初始化也不起作用：

And initializing like this also doesn't work:

int size = getDependentSizeForBitset();
myBitset = new bitset<size>();

推荐答案

Boost具有 dynamic_bitset 即可使用。

Boost has a dynamic_bitset you can use.

或者，您可以使用 vector< bool> ，（不幸的是）它专门用作位集。这引起了很多混乱，通常被认为是一个坏主意。但这就是它的工作方式，所以我想，如果您需要它，那么不妨使用它。

Alternatively, you can use a vector<bool>, which (unfortunately) is specialized to act as a bitset. This causes a lot of confusion, and in general is considered a bad idea. But that's how it works, so if that's what you need, you might as well use it, I suppose.

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