错误C2679:二进制'<<' :未找到采用'std :: string'类型的右侧操作数的运算符(或没有可接受的转换) [英] error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::string' (or there is no acceptable conversion)

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本文介绍了错误C2679:二进制'<<' :未找到采用'std :: string'类型的右侧操作数的运算符(或没有可接受的转换)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是我的代码,如何解决此错误?

Here's my code, how do I fix this error?

#include "stdafx.h"
#include <iostream>

using namespace std;

int main()
{
    string title = "THE WORLD OF PIRATES";
    cout << title << endl;
    cout << " Welcome to the world of pirates";

    cin.get();

    return 0;
}

错误是

binary '<<' : no operator found which takes a right-hand operand of type 'std::string' (or there is no acceptable conversion)


推荐答案

您忘记了 #include< string>

使用 std :: string 而不包含其标头可用于某些间接导入的编译器< string> 的部分放入其< iostream> 或其他标头中,但这不是标准的,不应该依靠。另外,当您尝试输出字符串时,它们通常会中断,因为它们仅包含实现的一部分,而缺少实现 operator<< 的那一部分。

using std::string without including it's header works on some compilers that indirectly import parts of <string> into their <iostream> or other headers but that's not standard and shouldn't be relied upon. Also they often break when you try to output a string since they only included a part of the implementation and are missing the part that implements the operator<<.

这篇关于错误C2679:二进制'&lt;&lt;' :未找到采用'std :: string'类型的右侧操作数的运算符(或没有可接受的转换)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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