我可以从Rust代码调用C或C ++函数吗？ [英] Can I call C or C++ functions from Rust code?

问题描述

是否可以在Rust中调用C或C ++函数？如果是这样，怎么办？

Is it possible to call C or C++ functions within Rust? If so, how is this done?

推荐答案

Rust不直接支持此功能，因此C ++函数符号修饰是实现定义的，因此它将需要Rust的大量支持才能处理此功能。这不是不可能，但可能不会发生。

Rust doesn't support this directly, C++ function symbol mangling is implementation defined, so it will need a lot of support from Rust to handle this feature. It's not impossible but it's probably not going to happen.

但是，Rust声称支持C语言。这显然更容易支持，因为它仅需要支持C的函数调用。这也是实现定义的行为，但这并没有太大变化，人们同意一起共享相同的约定，因此

However, Rust claims to support the C language. This is clearly more easy to support, as it "only" needs to support the function calls of C. This is implementation-defined behavior too, but this doesn't change a lot and people agree to work together to share the same convention so you will not have a problem to use C as intermediary on common platform.

因此，要从Rust调用C ++，必须通过C。

So, to call C++ from Rust, you must pass by C.

要从Rust调用C，请文档显示了此示例：

To call C from Rust, the docs show this example:

extern "C" {
    fn abs(input: i32) -> i32;
}

fn main() {
    unsafe {
        println!("Absolute value of -3 according to C: {}", abs(-3));
    }
}

要从C调用C ++，必须使用C ++函数定义为此：

To call C++ from C, a C++ function must be defined like this:

// This C++ function can be called from C code
extern "C" void handler(int) {
    std::cout << "Callback invoked\n"; // It can use C++
}

将此示例转换为Rust中的示例，给出：

To transmute this example to our example in Rust, that gives:

#include <cstdlib>
#include <cinttypes>

extern "C" std::int32_t abs(std::int32_t n) {
    return std::abs(static_cast<std::intmax_t>(n));
}

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