new / new []是否应与delete / delete []相匹配？ [英] Should new/new[] match delete/delete[]?

问题描述

我知道，当我们使用new / new []分配内存时，应该分别使用delete / delete []释放内存。

这里问题是

我可以使用delete []释放由new分配的内存吗？

例如，

  int * pInt3 = new int; 
 delete [] pInt3; 
 pInt3 = NULL; 
 
 T * pT3 =新的T； 
 delete [] pT3; 
 pT3 = NULL; 
  

谢谢

解决方案

否，您应该将非数组形式的 new 与非数组 delete 匹配，

请参见关于Freestore Management的C ++ FAQ Lite部分

这特别好： http://www.parashift.com/c%2B%2B-faq-lite/freestore-mgmt .html＃faq-16.12

[16.12]如果删除通过新T [n]分配的数组时忘记了[]怎么办？ / p>

所有生命都陷入了灾难性的终结。

在新T [n]与新的T [n]之间建立联系是程序员的责任，而不是编译器的责任。 delete [] p正确。如果弄错了，编译器将不会生成编译时消息或运行时错误消息。堆损坏可能是结果。或更糟。您的程序可能会死。

I knew that when we allocate memory by using new/new[], then we should release the memory by using the delete/delete[] respectively.

Here is the question,

Can I use delete[] to release the memory allocated by new?

For example,

int *pInt3 = new int;
delete [] pInt3;
pInt3 = NULL;

T *pT3 = new T;
delete [] pT3;
pT3 = NULL;

Thank you

解决方案

No, you should match the non-array form of new with non-array delete, and likewise for the array forms.

See the C++ FAQ Lite section on Freestore Management

This is especially good: http://www.parashift.com/c%2B%2B-faq-lite/freestore-mgmt.html#faq-16.12

[16.12] What if I forget the [] when deleteing array allocated via new T[n]?

All life comes to a catastrophic end.

It is the programmer's —not the compiler's— responsibility to get the connection between new T[n] and delete[] p correct. If you get it wrong, neither a compile-time nor a run-time error message will be generated by the compiler. Heap corruption is a likely result. Or worse. Your program will probably die.

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