没有这样的插槽/信号(Qt) [英] No such Slot/Signals (Qt)
问题描述
Object :: connect:没有这样的信号RollsRoyceTab :: signal_aValueChange(int aValue)
??????
Object::connect: No such signal RollsRoyceTab::signal_aValueChange(int aValue) ??????
我有
class RollsRoyceTab : public QWidget
{
Q_OBJECT
public:
RollsRoyceTab(QWidget *parent = 0);
public slots:
void aValueChange(int);
void bValueChange(int);
void cValueChange(int);
void rrValuesHolder(int aValue, int bValue, int cValue);
signals:
void signal_aValueChange(int aValue);
void signal_bValueChange(int bValue);
void signal_cValueChange(int cValue);
private:
.........
int aValue, bValue, cValue;
};
............
connect(this,SIGNAL(signal_aValueChange(int aValue)),this,SLOT(rrValuesHolder(int aValue, int bValue, int cValue)));
}
void RollsRoyceTab::aValueChange(int aValue)
{
lcdAL->display(aValue);
lcdAR->display(100 - aValue);
emit signal_aValueChange(aValue);
}
void RollsRoyceTab::rrValuesHolder(int aValue, int bValue, int cValue)
{
qDebug() << aValue;
qDebug() << bValue;
qDebug() << cValue;
}
并连接(......此插槽(rrValuesHolder(int aValue,int bValue,int cValue)));;还是只需要写一个值SLOT(rrValuesHolder(int aValue))?
and connect(...... this,SLOT(rrValuesHolder(int aValue, int bValue, int cValue))); or need write only one value SLOT(rrValuesHolder(int aValue)) ?
推荐答案
首先:QObject :: connect中的信号和插槽()应该没有变量名。
First: signals and slots in QObject::connect() should be without variables names.
第二个:您不能用一个带有三个参数的SLOT连接带有一个参数的信号。 SIGNAL的自变量不得少于SLOT。
Second: You can't connect signal with one argument with SLOT with three arguments. SIGNAL must not have fewer arguments than the SLOT.
例如:
connect(this,SIGNAL(signal_aValueChange(int)),this,SLOT(rrValuesHolder(int)));
这只是解释。如果您发出带有一个参数的信号(例如QString),那么插槽将如何知道另外两个参数是什么?对我来说,这是合乎逻辑的。
And it's simply explanation for that. If you emit signal with one argument (for e.g. QString) how would slot know what are others two arguments? For me it's logical.
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