在C ++中的头文件中声明的源文件中定义静态方法 [英] Define static method in source-file with declaration in header-file in C++

问题描述

在C ++中使用静态方法时遇到一些麻烦

I am having a little trouble working with static methods in C++

示例.h：

class IC_Utility {
public:
    IC_Utility();
    ~IC_Utility();

    std::string CP_PStringToString( const unsigned char *outString );
    void CP_StringToPString( std::string& inString, unsigned char *outString, short inMaxLength );
    static void CP_StringToPString( std::string& inString, unsigned char *outString);
    void CP_StringToPString( FxString& inString, FxUChar *outString);

};

示例.cpp：

static void IC_Utility::CP_StringToPString(std::string& inString, unsigned char *outString)
{
    short       length = inString.length();

   if( outString != NULL )
    {
        if( length >= 1 )
            CPLAT::CP_Utility::CP_CopyMemory( inString.c_str(), &outString[ 1 ], length );

            outString[ 0 ] = length;
    }
}

我想打这样的电话：

IC_Utility::CP_StringToPString(directoryNameString, directoryName );

但是我得到一个错误：

error: cannot declare member function 'static void IC_Utility::CP_StringToPString(std::string&, unsigned char*)' to have static linkage

我不明白为什么我不能这样做。谁能帮助我理解为什么以及如何实现我想要的东西？

I dont understand why I cannot do this. Can anyone help me understand why and how to achieve what I want?

推荐答案

删除静态关键字。只需在类定义中保留它即可。

Remove static keyword in method definition. Keep it just in your class definition.

static 关键字放置在.cpp文件中意味着某个函数具有一个静态链接，即它只能从同一文件中的其他函数访问。

static keyword placed in .cpp file means that a certain function has a static linkage, ie. it is accessible only from other functions in the same file.

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