调用构造函数而不创建对象 [英] Calling a constructor without creating object

问题描述

下面的代码中到底发生了什么。

What exactly is happening in the code below.

#include<iostream.h>

class Demo
{
    public :

    Demo()
    {
        cout<<"\nIn Demo const";
    }
    ~Demo()
    {
        cout<<"\nin demo dest";
    }
};

void main() {
    Demo();
}

Demo（）只需调用构造函数和析构函数即可。是否在此过程中创建对象？

Demo() simply calls the constructor and destructor. Is a object being created in this process? And thus is the memory being allocated?

推荐答案

您没有显式调用构造函数，而是这段代码创建了一个临时的未命名对象类型为 Demo ，在; 之后立即销毁。

You're not explicitly calling the constructor, instead this code creates a temporary unnamed object with type Demo, which is destroyed immediately after ;.

是的，为此临时对象分配了内存（自动在堆栈上），并在; 之后将其释放（再次自动）。同时，按预期方式调用了构造函数和析构函数。

Yes, memory is allocated (automatically, on the stack) for this temp object and it's freed (again automatically) after ;. Meanwhile, the constructor and destructor are called, as expected.

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