用C ++代码计算时间 [英] Calculating time by the C++ code

问题描述

我知道这个问题已经被问过几次了，但是没有一个人真的在帮助我，所以再问一次。

I know this question has been asked few times over SO but none of them is really helping me out, so asking again.

我正在使用Windows XP并运行Visual Studio C ++ 2008。

I am using windows xp and running visual studio c++ 2008.

我正在寻找的所有代码都在使用time.h，但我认为这可能在这里无法正常工作，因为结果使我感到怀疑。

All the code which i am looking is using time.h but i think may be its not working correctly here, because results are making me suspicious.

所以这就是我想要的。

star time = get time some how (this is my question)

my code

end time = get time some how (this is my question)

time passed = start time - end time

推荐答案

这是我使用的

void StartTimer( _int64 *pt1 )
{
   QueryPerformanceCounter( (LARGE_INTEGER*)pt1 );
}

double StopTimer( _int64 t1 )
{
   _int64 t2, ldFreq;

   QueryPerformanceCounter( (LARGE_INTEGER*)&t2 );
   QueryPerformanceFrequency( (LARGE_INTEGER*)&ldFreq );
   return ((double)( t2 - t1 ) / (double)ldFreq) * 1000.0;
}

像这样使用：

    _int64 t1;

    StartTimer( &t1 );

    // do some stuff

    printf( "Time = %.3f\n", StopTimer( t1 ));

这篇关于用C ++代码计算时间的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！