如何获得枚举的基本类型？ [英] How do I get the fundamental type of an enum?

问题描述

带有如下声明：

enum DrawBoldMode : unsigned
{
    DBM_NONE =              0,
    DBM_ITEM =              1<<0,   // bold just the nearest line
    DBM_SECTION =           1<<1,   // bold all lines in the same section
    DBM_LINETYPE =          1<<2,   // bold all lines of the same line type
    DBM_POINTAGE =          1<<3,   // bold all lines of the same line type
};

如何获取DrawBoldMode的基础类型（即未签名）？

How can I derive the underlying type of DrawBoldMode (i.e. unsigned)?

推荐答案

它应该以 std :: underlying_type< DrawBoldMode> :: type 的形式提供。但是，我的编译器（GCC 4.6.1）似乎并未实现。

It should be available as std::underlying_type<DrawBoldMode>::type. However, my compiler (GCC 4.6.1) doesn't seem to implement that.

我认为不可能用模板来实现，但是我对此可能是错的。

I think it's impossible to implement it with templates, but I could be wrong about that.

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