传递模板方法作为参数 [英] Pass a template method as an argument
本文介绍了传递模板方法作为参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有人可以帮我实现该代码吗?
Could some one help me how to implement this code?
我需要将一个函数传递给另一个函数:
I need to pass a function to another function:
std::cout << process_time(Model::method1) << std::endl;
此函数以模板类型获取该函数并在对象上调用
This function gets the function as a template type and calls it on an object
template <typename F>
double process_time(F algorithm)
{
Model model;
double time=0;
do
{
// ...
time += model.algorithm(arg1);
} while (! stop_criteria);
return time;
}
请注意,方法1
也是一个功能模板:
Note that method1
is a function template as well:
template <typename T>
double method1(std::vector<T> &v)
{
...
}
它的法律语法是什么?
main.cpp
#include <iostream>
#include <vector>
class Model
{
public:
template <typename T>
double method1(std::vector<T> &v)
{
double t = 0;
//...
return t;
}
template <typename T>
double method2(std::vector<T> &v)
{
double t = 0;
//...
return t;
}
};
template <typename F>
double process_time(F algorithm)
{
Model model;
double time = 0;
bool stop_criteria = false;
do
{
std::vector<int> arg1;
// ...
time += model.algorithm(arg1);
} while (!stop_criteria);
return time;
}
int main()
{
std::cout << process_time(Model::method1) << std::endl;
return 0;
}
推荐答案
这是最接近您的编译的代码:
This is the closest to your code that compiles:
#include <iostream>
#include <vector>
struct Model {
template <typename T>
double method1(std::vector<T> &v) {
double t = 0;
//...
return t;
}
};
template <typename F>
double process_time(F algorithm) {
Model model;
double time = 0;
bool stop_criteria = false;
do
{
std::vector<int> arg1;
// ...
time += (model.*algorithm)(arg1);
} while (!stop_criteria);
return time;
}
int main() {
std::cout << process_time(&Model::method1<int>) << std::endl;
}
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