代码中奇怪的constexpr参数 [英] Weird constexpr argument in code
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问题描述
我正在尝试理解代码:
#include <iostream>
#include <stdexcept>
// constexpr functions use recursion rather than iteration
constexpr int factorial(int n)
{
return n <= 1 ? 1 : (n * factorial(n-1));
}
// literal class
class conststr {
const char * p;
std::size_t sz;
public:
template<std::size_t N>
constexpr conststr(const char(&a)[N]) : p(a), sz(N-1) {}
// constexpr functions signal errors by throwing exceptions from operator ?:
constexpr char operator[](std::size_t n) const {
return n < sz ? p[n] : throw std::out_of_range("");
}
constexpr std::size_t size() const { return sz; }
};
constexpr std::size_t countlower(conststr s, std::size_t n = 0,
std::size_t c = 0) {
return n == s.size() ? c :
s[n] >= 'a' && s[n] <= 'z' ? countlower(s, n+1, c+1) :
countlower(s, n+1, c);
}
// output function that requires a compile-time constant, for testing
template<int n> struct constN {
constN() { std::cout << n << '\n'; }
};
int main()
{
std::cout << "4! = " ;
constN<factorial(4)> out1; // computed at compile time
volatile int k = 8; // disallow optimization using volatile
std::cout << k << "! = " << factorial(k) << '\n'; // computed at run time
std::cout << "Number of lowercase letters in \"Hello, world!\" is ";
constN<countlower("Hello, world!")> out2; // implicitly converted to conststr
}
参数是什么
const char(&a)[N]
?我不明白..似乎是对数组的引用..将它传递给constexpr构造函数有什么意义?
? I don't understand it.. seems like a reference to an array.. and what's the point in passing it to a constexpr constructor?
推荐答案
参数 const char(& a)[N]
是对数组的引用。
The parameter const char(&a)[N]
is a reference to an array.
它的要点是它允许编译器推断数组的长度。如果没有引用,作为参数的 const char a [N]
等效于 const char * a
而不是允许推导模板参数 N
。
The point of it is that it allows the compiler to deduce the length of the array. Without the reference, const char a[N]
as parameter would be equivalent to const char* a
which doesn't allow the template parameter N
to be deduced.
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