销毁thread_local对象 [英] Destruction of thread_local objects
问题描述
在问题从多个线程使用QSqlQuery 时,结果表明线程存储解决了问题。
In the question Using QSqlQuery from multiple threads there was the outcome that thread storage solves the problem.
我编写了一个简单的演示代码,以明确了解C ++ 11 thread_local说明符。下面的代码创建两个线程,这些线程具有ThreadLocal对象作为本地唯一对象。 Storage :: get函数是特定于线程的单例。标准是否保证在连接或退出线程函数时调用ThreadLocal析构函数?
I made a simple demo code to be absolutely clear about C++11 thread_local specifier. The code below creates two threads which have ThreadLocal object as a local unique object. The Storage::get function is a thread specific singleton. Does the standard guarantee that ThreadLocal destructor is called on join or the exit of the thread function?
与GCC 5.4.0
一起编译(g ++ -o main main.cpp --std = c ++ 11 -lpthread)
Compiled with GCC 5.4.0 (g++ -o main main.cpp --std=c++11 -lpthread)
#include <thread>
#include <mutex>
#include <string>
#include <chrono>
#include <iostream>
#include <atomic>
static std::mutex mtx;
struct ThreadLocal {
std::string name;
~ThreadLocal() {
mtx.lock();
std::cout << "destroy " << name << std::endl;
mtx.unlock();
}
};
struct Storage {
static ThreadLocal &get() {
/* Thread local singleton */
static thread_local ThreadLocal l;
static std::atomic<int> cnt(0);
l.name = std::to_string(cnt);
cnt++;
return l;
}
};
void thread() {
mtx.lock();
std::cout << Storage::get().name << std::endl;
mtx.unlock();
std::this_thread::sleep_for(std::chrono::seconds(1));
}
int main(int argc, const char **argv) {
std::thread t1(&thread);
std::thread t2(&thread);
t1.join();
t2.join();
}
推荐答案
如果对象是构造好的,它将在线程功能退出时销毁。 [basic.stc.thread ] / 2 :
If the object was constructed, it will be destroyed on the exit of the thread function. Pretty much in those exact words over at [basic.stc.thread]/2:
具有线程存储持续时间的变量应在
首次使用odr之前初始化( [basic.def.odr]),并且如果构造了
,则在线程退出时将其销毁。
A variable with thread storage duration shall be initialized before its first odr-use ([basic.def.odr]) and, if constructed, shall be destroyed on thread exit.
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