如果路径中的每个元素都不存在，则创建一个目录 [英] Create a directory for every element of a path if it does not exist

问题描述

在C ++中，我想从路径 path / that / consists / of / several / elements 创建目录。我还想创建该目录的所有父目录，以防它们不存在。

In C++, I want to create a directory from a path "path/that/consists/of/several/elements". Also I want to create all parent directories of that directory in case they are not existing. How to do that with std C++?

推荐答案

std :: experimental ::文件系统 / std :: filesystem （C ++ 14 / C ++ 17）提供 create_directories（） 。如果尚不存在，它将为每个路径元素创建一个目录。为此，它执行 create_directory（） 中的每个这样的元素。

std::experimental::filesystem/std::filesystem (C++14/C++17) provides create_directories(). It creates a directory for every path element if it does not already exist. For that it executes create_directory() for every such element.

#include <experimental/filesystem>
#include <iostream>

int main()
{
    namespace fs = std::experimental::filesystem; // In C++17 use std::filesystem.

    try {
        fs::create_directories("path/with/directories/that/might/not/exist");
    }
    catch (std::exception& e) { // Not using fs::filesystem_error since std::bad_alloc can throw too.
        std::cout << e.what() << std::endl;
    }

    return 0;
}

如果异常处理不合适，请 std :: filesystem 函数使用 std :: error_code ：

If exception handling does not fit, std::filesystem functions have overloads using std::error_code:

int main() {
    namespace fs = std::experimental::filesystem; // In C++17 use std::filesystem.

    std::error_code ec;
    bool success = fs::create_directories("path/with/directories/that/might/not/exist", ec);

    if (!success) {
        std::cout << ec.message() << std::endl; // Fun fact: In case of success ec.message() returns "The operation completed successfully." using vc++.
    }

    return 0;
}

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