在WinXP中如何隐藏进程窗口（从任务栏）来创建进程？与CreateProcess功能？ [英] How could i Create a process with hiding the process window (from the task bar) in winXP? with CreateProcess function?

问题描述

 /* CreateProcess initialization */
 STARTUPINFO si;
 PROCESS_INFORMATION pi;

 memset(&si, 0, sizeof(si));
 memset(&pi, 0, sizeof(pi));
 si.cb = sizeof(si);

 long ret;
 // si.wShowWindow = SW_HIDE;
 // hide process window.... // run in background..

 si.dwFlags = STARTF_USESHOWWINDOW;
 si.wShowWindow = SW_HIDE;

 if (!CreateProcess(0, exe,
        0, 0, 1, NORMAL_PRIORITY_CLASS, 0, 0, &si, &pi)) {
    return;
 }
 //int prez = WaitForSingleObject(pi.hProcess, INFINITE);

 //CloseHandle(pi.hProcess);

推荐答案

您可以尝试设置dwFlags 成员rel = noreferrer> STARTUPINFO 结构到 STARTF_USESHOWWINDOW 和 wShowWindow SW_HIDE 的成员。

You can attempt to set the dwFlags member of your STARTUPINFO structure to STARTF_USESHOWWINDOW and the wShowWindow member to SW_HIDE.

这将使 CreateProcess（）传递0作为nCmdShow 参数.aspx rel = noreferrer> WinMain 。但是，并非所有Windows应用程序的行为都很好，并在初始调用 ShowWindow（）时使用此值。

This will make CreateProcess() pass 0 as the nCmdShow parameter of WinMain. However, not all Windows application are well behaved and use this value to the initial call to ShowWindow().

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