有没有办法使捕获在正则表达式中重复任意次数？ [英] Is there a way to have a capture repeat an arbitrary number of times in a regex?

问题描述

我正在将C ++ tr1 :: regex与ECMA regex语法一起使用。我想做的是解析标头并返回与标头中每个项目相关的值。

I'm using the C++ tr1::regex with the ECMA regex grammar. What I'm trying to do is parse a header and return values associated with each item in the header.

Header：

-Testing some text
-Numbers 1 2 5
-MoreStuff some more text
-Numbers 1 10

我想做的是找到所有的 -Numbers行，并用一个正则表达式将每个数字放入自己的结果中。如您所见，-Numbers行中可以有任意数量的值。目前，我只是在搜索 -Numbers（[\s0-9] +），然后将该结果标记化。我只是想知道是否可以在单个正则表达式中查找和标记结果。

What I would like to do is find all of the "-Numbers" lines and put each number into its own result with a single regex. As you can see, the "-Numbers" lines can have an arbitrary number of values on the line. Currently, I'm just searching for "-Numbers([\s0-9]+)" and then tokenizing that result. I was just wondering if there was any way to both find and tokenize the results in a single regex.

推荐答案

不，有不是。

这篇关于有没有办法使捕获在正则表达式中重复任意次数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！