如何进行不区分大小写的字符串比较？ [英] How do I do a case-insensitive string comparison?

问题描述

如何在Python中执行不区分大小写的字符串比较？

How can I do case insensitive string comparison in Python?

我想使用非常简单且Pythonic的方法将常规字符串与存储库字符串的比较封装在一起办法。我还希望能够使用常规python字符串在由字符串散列的字典中查找值。

I would like to encapsulate comparison of a regular strings to a repository string using in a very simple and Pythonic way. I also would like to have ability to look up values in a dict hashed by strings using regular python strings.

推荐答案

假定ASCII字符串：

Assuming ASCII strings:

string1 = 'Hello'
string2 = 'hello'

if string1.lower() == string2.lower():
    print("The strings are the same (case insensitive)")
else:
    print("The strings are NOT the same (case insensitive)")

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