shell脚本中字符串的不区分大小写比较 [英] Case insensitive comparison of strings in shell script

问题描述

== 运算符用于在shell脚本中比较两个字符串。但是，我想比较两个字符串忽略的情况，怎么办呢？是否有任何标准命令？

解决方案

如果你有bash

  str1 =MATCH
 str2 =match
 shopt -s nocasematch 
 case$ str1in 
 $ str2） echomatch;; 
 *）echono match;; 
 esac 
  

否则，你应该告诉我们你使用的shell。

使用awk

  str1 =MATCH
 str2 = match
 awk -vs1 =$ str1-vs2 =$ str2'BEGIN {
 if（tolower（s1）== tolower（s2））{
 print 
} 
}'
  

The == operator is used to compare two strings in shell script. However, I want to compare two strings ignoring case, how can it be done? Is there any standard command for this?

解决方案

if you have bash

str1="MATCH"
str2="match"
shopt -s nocasematch
case "$str1" in
 $str2 ) echo "match";;
 *) echo "no match";;
esac

otherwise, you should tell us what shell you are using.

alternative, using awk

str1="MATCH"
str2="match"
awk -vs1="$str1" -vs2="$str2" 'BEGIN {
  if ( tolower(s1) == tolower(s2) ){
    print "match"
  }
}'

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