是否可以重载* static_cast *运算符？ [英] Is it possible to overload the *static_cast* operator?

问题描述

我定义了一个类 A ，实际的属性无关紧要。是否可以定义 static_cast< class T>（int）运算符的特殊化，以将整数转换为A类？

I have defined a class A, the actual properties are irrelevant. Is it possible to define a specialization of the static_cast<class T>(int) operator to convert from integers to class A?

到目前为止，我一直在通过定义 convert 函数来做到这一点，例如 convert（int）。但是我宁愿使用 static_cast 与其他转化保持一致。

So far I have been doing this by defining a convert function, such as A convert(int). But I would rather use static_cast for consistency with other conversions.

有可能吗？

我还想避免隐式转换，这就是为什么我不通过 A做到这一点

Is it possible?
I also want to avoid implicit conversions, which is why I'm not doing this through A's constructor.

推荐答案

static_cast 是语言关键字，您无能为力。但是，您可以 使用显式转换构造函数实现目标：

static_cast is a language keyword and you can't do anything to change that. However you can achieve what you what with an explicit converting constructor:

class Foo
{
public:
    explicit Foo(int bar) { }  // Can't be called implicitly, CAN be invoked with `static_cast`.
};

之所以有效，是因为该语言定义了 static_cast '对象构造方面的行为，并酌情调用转化。

This works because the language defines static_cast's behavior in terms of object construction, invoking conversions as appropriate.

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