Symfony2-在树枝中将字符串转换为Int [英] Symfony2 - Cast a String to Int in twig

问题描述

我想知道是否可以在细枝中将String转换为Int。我尝试查看用户是否有足够的信用来购买币。为此，我使用模板中的渲染来计算功劳金额（因为我需要模板中的值，但我没有找到更好的方法来做...）：

I would like to know if it was possible to cast a String to an Int in twig. I try to see if a user has enough credit or not to buy a cours. For that, I calculate the amount of credit with a render in the template (because I need the value in the template, and I didn't found a better way to do it...) like this :

{% set creditUser %}
    {{render(controller('L3L2EntraideBundle:Credits:sommeCredits'))}}
{% endset %}

但是当我尝试比较creditUser时：

But when I try to compare creditUser :

{% if creditUser < c.idCompetenceCours.prix %}disabled="false"{% endif %}

Symfony返回我一个美丽的错误：在第21行的L3L2UserBundle：Profile：modal_prendre_rdv.html.twig中的模板渲染过程中引发了异常（注意：Twig_Markup类的对象无法转换为int）。

Symfony return me a beautiful error : An exception has been thrown during the rendering of a template ("Notice: Object of class Twig_Markup could not be converted to int") in L3L2UserBundle:Profile:modal_prendre_rdv.html.twig at line 21.

有什么想法吗？预先感谢您对Stackoverflow的第一个问题，对不起我的英语。

Any idea ? Thank you in advance for my first question on Stackoverflow and sorry for my english.

推荐答案

这不是字符串，而是Twig_Markup

This is not string but Twig_Markup

{% if creditUser.__toString < c.idCompetenceCours.prix %}

但这不是一个好方法，您应该从object /变量不是来自呈现的模板

but this is not good approach you should get this value from object/variable not from rendered template

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