\n的C ++测试 [英] C++ testing for \n
本文介绍了\n的C ++测试的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试学习C ++,一种练习是构建一个命令行工具,该工具接受用户输入并将其存储在char数组中,直到用户输入空白行为止。我认为我的骨骼是正确的,但是无论出于何种原因,我的身体都在不断运转。我的代码如下:
I'm attempting to learn C++ and one exercise is to build a command line tool that accepts user input and stores it in a char array until the user enters a blank line. I think I have the skeleton right but for whatever reason my while runs continuously. My code is as follows:
char a[256];
//while the first character isn't a new line
while (a[0] != '\n') {
//get the char array
cin >> a;
cout << a;
}
任何帮助将不胜感激。
推荐答案
使用 operator>>
无法检测到换行符。对于大多数类型,它使用空格作为分隔符,并且不区分空格,制表符或换行符。改用getline:
You can't detect newlines with operator>>
. For most types, it uses whitespace as a delimiter, and it doesn't differentiate between spaces, tabs or newlines. Use getline instead:
for (std::string line; std::getline(std::cin, line); )
{
if (line.empty())
{
// if the line is empty, that means the user didn't
// press anything before hitting the enter key
}
}
这篇关于\n的C ++测试的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文