getchar（）在c中不起作用 [英] getchar() not working in c

问题描述

getchar（）在以下程序中不起作用，任何人都可以帮助我解决此问题。我尝试用scanf（）函数代替getchar（），但是它也不起作用。

getchar() is not working in the below program, can anyone help me to solve this out. I tried scanf() function in place of getchar() then also it is not working.

我无法找出问题的根本原因，有人

I am not able to figure out the root cause of the issue, can anyone please help me.

#include<stdio.h>
int main()
{
        int x, n=0, p=0,z=0,i=0;
        char ch;

        do
        {
                printf("\nEnter a number : ");
                scanf("%d",&x);

                if (x<0)
                        n++;
                else if (x>0)
                        p++;
                else
                        z++;

                printf("\nAny more number want to enter : Y , N ? ");
                ch = getchar();

                i++;

        }while(ch=='y'||ch=='Y');
        printf("\nTotal numbers entered : %d\n",i);
        printf("Total Negative Number : %d\n",n);
        printf("Total Positive number : %d\n",p);
        printf("Total Zero            : %d\n",z);
        return 0 ;
}

该代码已从 Yashvant Kanetkar书中复制

The code has been copied from the book of "Yashvant Kanetkar"

推荐答案

这是因为 scanf（）在输入中留下了结尾的换行符。

That's because scanf() left the trailing newline in input.

我建议替换为：

ch = getchar();

使用：

scanf(" %c", &ch);

请注意格式字符串中的前导空格。需要强制 scanf（）忽略每个空格字符，直到读取非空格为止。通常，这比在以前的 scanf（）中使用单个字符更健壮，因为它忽略了任何个空格。

Note the leading space in the format string. It is needed to force scanf() to ignore every whitespace character until a non-whitespace is read. This is generally more robust than consuming a single char in the previous scanf() because it ignores any number of blanks.

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