Scanf在C中不起作用 [英] Scanf is not working in C

问题描述

我正在尝试弄清为什么第二个scanf对我不起作用.这是代码:

I am trying to work out why the second scanf is not working for me. Here is the code:

#include <stdio.h>
int main() {
     char n;int p;
     printf("Enter the number: ");
     scanf("%d",&p);
     if(p==1) {
          printf("Enter a character: ");
          scanf("%c",&n);
     }
}

在此程序中，第二个 scanf(％c"，& n)不起作用.我究竟做错了什么?上面程序的输出是:

In this program the second scanf("%c",&n) is not working. What am I doing wrong? The output of above program is:

Enter a number: 1
Enter a charter: 

它是从编译器中出来的.

It is coming out of compiler.

推荐答案

这是因为先前的 scanf()在输入缓冲区中留下了换行符.一个简单的解决方法，告诉scanf忽略所有空格:

It's because the previous scanf() left a newline in the input buffer. A simple fix to tell scanf to ignore all the whitespaces:

scanf(" %c",&n); //Note the space before %c

格式字符串中的任何空格指令(空格， \ n 等)都告诉scanf忽略输入中任意数量的空格.

Any whitespace directive ( space, \n etc) in the format string tells scanf ignore any number of whitespaces in the input.

来自 scanf() 手册:

   A sequence of white-space characters (space, tab, newline,
          etc.; see isspace(3)).  This directive matches any amount of
          white space, including none, in the input.

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