Swift：仅在开头删除字符串的特定字符 [英] Swift: Remove specific characters of a string only at the beginning

问题描述

我在寻找答案，但还没有找到答案，所以：

i was looking for an answer but haven't found one yet, so:

例如：我有一个字符串，例如 #blablub，我想删除开头的＃，我可以简单地删除第一个字符。但是，如果我有一个带有 #### bla＃blub的字符串，而我只想只在第一个字符串的开头删除所有的＃，我不知道如何解决这个问题。

For example: i have a string like "#blablub" and i want to remove the # at the beginning, i can just simply remove the first char. But, if i have a string with "#####bla#blub" and i only want to remove all # only at the beginning of the first string, i have no idea how to solve that.

我的目标是得到像这样的字符串 bla＃blub，否则使用replaceOccourencies可以很容易...

My goal is to get a string like this "bla#blub", otherwise it would be to easy with replaceOccourencies...

希望您能提供帮助。

推荐答案

Swift2

Swift2

func ltrim(str: String, _ chars: Set<Character>) -> String {
    if let index = str.characters.indexOf({!chars.contains($0)}) {
        return str[index..<str.endIndex]
    } else {
        return ""
    }
}

Swift3

Swift3

func ltrim(_ str: String, _ chars: Set<Character>) -> String {
    if let index = str.characters.index(where: {!chars.contains($0)}) {
        return str[index..<str.endIndex]
    } else {
        return ""
    }
}

用法：

ltrim("#####bla#blub", ["#"]) //->"bla#blub"

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