如何在厨师ruby_block中要求我的图书馆 [英] how to require my library in chef ruby_block

问题描述

我正在开发用于部署简单ROR应用程序的食谱。我编写了一个app_helper.rb并将其放入我的食谱的库目录中，内容如下：

I'm developing a cookbook to deploy a simple ROR application. I write an app_helper.rb and put it into the libraries directory of my cookbook, here is the content:

module AppHelper

    def self.find_gem
      if File.exists?("/usr/local/rvm/bin/rvm")
        return `/usr/local/rvm/bin/rvm default exec which gem`.chomp
      else
        return "/usr/bin/gem"
      end
    end
  end

在配方/default.rb中，我将上述模块混入Chef :: Recipe类

In the recipes/default.rb, I mix in the above module into Chef::Recipe class

class Chef::Recipe
  include AppHelper
end

如您所知，可以在配方的任何位置调用find_gem函数。

As you know, the find_gem function can be called from anywhere of the recipe.

当我尝试在自己的计算机中使用find_gem函数时ruby_block像这样：

when I'm trying to use the find_gem function in my ruby_block like this:

ruby_block "find gem" do
   block do
    gem_bin = Chef::Recipe::find_gem
    # or gem_bin = find_gem
  end
end

我有一个NoM ethodError：未定义的方法'find_gem'。

I got a NoMethodError: undefined method 'find_gem'.

也尝试将模块混入Chef :: Resource :: RubyBlock中，这两种方法都不起作用。

Also try to mix in the module into Chef::Resource::RubyBlock, it doesn't work neither.

class Chef::Resource::RubyBlock
  include AppHelper
end

ruby_block "find gem" do
   block do
    gem_bin = Chef::Resource::RubyBlock::find_gem
    # or gem_bin = find_gem
  end
end

有没有办法从ruby_block调用模块中的函数？或者是否有Chef的变量来在库中定位文件，以便我可以在ruby_block中要求该模块。

Is there any way to call the function in the module from the ruby_block? Or Is there an variable of chef to location the files in the libraries, so that I can be able to require the module in the ruby_block.

谢谢！

推荐答案

根据加载顺序，您可能会

Depending on load order, you might be including your module into an anonymous Ruby class instead of what you think.

如果要在配方中使用方法，请在配方顶部执行以下操作：

If you want to use your method in a recipe, do this at the top of your recipe:

include AppHelper

您也可以在库的末尾使用：send ：

You could alternatively use :send at the end of your library:

Chef::Recipe.send(:include, AppHelper)

这是不同的，因为它如果未定义 Chef :: Recipe （如果不存在则在创建新类），则将引发异常。

This is different because it will raise an exception if Chef::Recipe is not defined (whereas you are creating a new class if it doesn't exist).

这就是您需要做的，除非您想在 not_if 和 only_if 中使用帮助器。守卫。然后，您需要在资源中包含帮助程序：

That's all you should need to do unless you want to use the helper in not_if and only_if guards. Then you need to include the helper in the resource:

Chef::Resource.send(:include, AppHelper)

---

好吧，既然我已经解释了所有这些，它将不会不能真正帮助您。 Ruby Block提供者只需调用该块-它不会实例评估它。因此，在资源中包含帮助程序不会做任何事情。

---

Okay, now that I explained all of that, it won't actually help you. The Ruby Block provider simply calls the block - it doesn't instance eval it. So including the helper in the resource doesn't do anything.

因此，在这种情况下，您需要使用单例对象（这是我能可靠想到的唯一解决方案）。定义方法的方式可以直接从全局命名空间调用：

So, you'll need to use a singleton object in this instance (it's the only solution I can reliably think of). The way you've defined your method, you can call it directly from the global namespace:

AppHelper.find_gem('...')

所以：

ruby_block "find gem" do
  block do
    gem_bin = AppHelper.find_gem('...')
  end
end

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