如何在Mac OS X Mavericks上的std C ++库中链接? [英] How to link in std C++ library on Mac OS X Mavericks?
问题描述
我正在将应用程序移植到OS X Darwin,并且遇到链接错误,缺少符号,例如:
I'm porting an application to OS X Darwin and am getting link errors with missing symbols like:
std::__1::basic_string<char, std::__1::char_traits<char>,
std::__1::allocator<char> >::find_last_of(char const*,
unsigned long,
unsigned long) const
operator delete[](void*)
typeinfo for std::runtime_error
std::set_unexpected(void (*)())
std::exception::~exception()
[...]
我希望它们应该来自libstdc ++,但我看不出如何在使用clang时进行链接。
I expect these should come from libstdc++ but I don't see how to link that in using clang.
这是我尝试的链接线和导致的失败:
Here is my attempted link line and the resulting failure:
clang -std=c++11 -stdlib=libc++ -m64 -o ARCH.darwin_1310_i86/release/myExec ARCH.darwin_1310_i86/release/myExec.o ../../src/netcomm/ARCH.darwin_1310_i86/release/libmyExec.a ../../src/common/ARCH.darwin_1310_i86/release/libcommon.a -L../zlib -lz -L../Botan -lbotan-1.10 -lboost_thread-mt
Undefined symbols for architecture x86_64:
"std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >::find_last_of(char const*, unsigned long, unsigned long) const", referenced from:
[...]
但是这没有用,我没有找到任何如何正确链接的示例。
But this did not work, I'm not finding any examples of how to link it in correctly.
推荐答案
您需要将 -lc ++
添加到链接行,如下所示:
You need to add -lc++
to the link line like this:
clang -std = c ++ 11 -stdlib = libc ++ -lc ++ -m64 -o ARCH.darwin_1310_i86 / release / myExec ARCH.darwin_1310_i86 / release / myExec.o ../../src/netcomm/ARCH。 darwin_1310_i86 / release / libmyExec.a ../../src/common/ARCH.darwin_1310_i86/release/libcommon.a -L ../ zlib -lz -L ../ Botan -lbotan-1.10 -lboost_thread-mt
clang -std=c++11 -stdlib=libc++ -lc++ -m64 -o ARCH.darwin_1310_i86/release/myExec ARCH.darwin_1310_i86/release/myExec.o ../../src/netcomm/ARCH.darwin_1310_i86/release/libmyExec.a ../../src/common/ARCH.darwin_1310_i86/release/libcommon.a -L../zlib -lz -L../Botan -lbotan-1.10 -lboost_thread-mt
添加之后,缺少的符号消失。
After adding that, the missing symbols go away.
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