自动初始化实例变量？ [英] Automatically initialize instance variables?

问题描述

我有一个看起来像这样的python类：

I have a python class that looks like this:

class Process:
    def __init__(self, PID, PPID, cmd, FDs, reachable, user):

后跟：

        self.PID=PID
        self.PPID=PPID
        self.cmd=cmd
        ...

有没有办法自动初始化这些实例变量，例如C ++的初始化列表？

Is there any way to autoinitialize these instance variables, like C++'s initialization list? It would spare lots of redundant code.

推荐答案

您可以使用装饰器：

from functools import wraps
import inspect

def initializer(func):
    """
    Automatically assigns the parameters.

    >>> class process:
    ...     @initializer
    ...     def __init__(self, cmd, reachable=False, user='root'):
    ...         pass
    >>> p = process('halt', True)
    >>> p.cmd, p.reachable, p.user
    ('halt', True, 'root')
    """
    names, varargs, keywords, defaults = inspect.getargspec(func)

    @wraps(func)
    def wrapper(self, *args, **kargs):
        for name, arg in list(zip(names[1:], args)) + list(kargs.items()):
            setattr(self, name, arg)

        for name, default in zip(reversed(names), reversed(defaults)):
            if not hasattr(self, name):
                setattr(self, name, default)

        func(self, *args, **kargs)

    return wrapper

使用它来装饰 __ init __ 方法：

class process:
    @initializer
    def __init__(self, PID, PPID, cmd, FDs, reachable, user):
        pass

输出：

>>> c = process(1, 2, 3, 4, 5, 6)
>>> c.PID
1
>>> dir(c)
['FDs', 'PID', 'PPID', '__doc__', '__init__', '__module__', 'cmd', 'reachable', 'user'

这篇关于自动初始化实例变量？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！