如何使子类实现接口？ [英] How to make a subclass implement an interface?

问题描述

我创建了一个类和一个子类。我在父类中也有一个接口。如何使子类实现该接口？

I have created a class and a subclass. I also have an interface in the parent class. How can I make the child class implement the interface?

代码为：

class Car
{ 
    public interface ISmth
    {
        void MyMethod();
    }
}
class MyCar : Car
{ 
    //implement the interface 
}

推荐答案

这应该是您代码的布局方式。

This is how your code should probably be laid out.

public interface ISmth
{
    void MyMethod();
}

class Car
{
}

class MyCar : Car, ISmth
{
    public void MyMethod()
    {
    }
}

没有似乎是将 ISmth 嵌套在 Car 车中的原因，但是如果您有，肯定可以做到。

There doesn't seem to be a reason to nest ISmth in Car, but if you do have one you certainly could do it.

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