从JSON创建CLOB属性 [英] Create CLOB property from JSON

问题描述

我已将实体导入为Maven依赖项，看起来像这样（简化）

I have Entity imported like a Maven dependency, looks like this(simplified)

@Entity
public class Person extends Base {

    private String name;

    private Clob biography;
//Getters and setters

我使用POST方法接收此JSON

And I receive this JSON with method POST

{"name":"John Doe",
"biography":"dragonborn"}

我收到此错误

"status": 400,
    "error": "Bad Request",
    "exception": "org.springframework.http.converter.HttpMessageNotReadableException",
    "message": "Could not read document: Can not construct instance of java.sql.Clob, 
problem: abstract types either need to be mapped to concrete types, have custom deserializer, or be instantiated with additional type information\n at
 [Source: java.io.PushbackInputStream@39e31d6a; line: 2, column: 13] (through reference chain: com.example.Person[\"biography\"]); 
nested exception is com.fasterxml.jackson.databind.JsonMappingException: 
Can not construct instance of java.sql.Clob, 
problem: abstract types either need to be mapped to concrete types, have custom deserializer, or be instantiated with additional type information\n 
at [Source: java.io.PushbackInputStream@39e31d6a; line: 2, column: 13] (through reference chain: com.example.Person[\"biography\"])",
    "path": "/persons"

如果传记是字符串，则创建Person。
如何将JSON属性转换为java.sql.Clob属性？
最佳的解决方案是调整ObjectMapper，但我很乐意听到任何建议。

If "biography" was String, Person is created. How can i convert JSON property to java.sql.Clob property? The best solution will tuning ObjectMapper, but i would be glad to hear any advices. Thanks!

推荐答案

只用

@Lob
String biography

在DDL中，数据库启动列为CLOB

And in DDL for database initiate column as CLOB

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