从 JSON 创建菜单 [英] Creating a Menu from JSON

问题描述

我正在尝试使用 jQuery UI 创建动态菜单.

I am trying to create a dynamic menu using jQuery UI.

我将从 JSON 文件中获取条目并创建我的菜单项.我决定先做一个小演示，然后再进行更大规模的尝试.这是我的小提琴，它按我希望的方式工作.现在我无法让它与 JSON 文件一起使用.

I will be fetching entries from a JSON file and creating my menu items.I decided to do a small demo before i try this on a larger scale.Here's my fiddle which works the way i want it to work. Now I cant get this to work with a JSON file.

工作小提琴

这里是 JSON

var JSON = 
    {
       menu: 
          [
             {name: 'Croatia', link: '0', sub: null},
             {name: 'England', link: '1', sub: 
                [
                   {name: 'Arsenal',link: '0-0', sub: null},
                   {name: 'Liverpool',link: '0-1', sub: null},
                   {name: 'Manchester United',link: '0-2', sub: null}
                ]
             },
             {name: 'Spain', link: '2', sub: 
                [
                   {name: 'Barcelona',link: '2-0', sub: null},
                   {name: 'Real Madrid',link: '2-1', sub: null}
                ]
              },        
              {name: 'Germany', link: '3',sub: 
                [
                   {name: 'Bayern Munich',link: '3-1', sub: null},
                   {name: 'Borrusia Dortmund',link: '3-2', sub: null}
                ]
              }
          ]
    }

如何使用 JSON 中的值设计我的整个菜单，其中 Li 将类似于以下内容.

How can i design my entire menu using the values from the JSON where the Li's will be something like the following.

<li><a href="#3-2">Borrusia Dortmund</a>
</li>

这个问题听起来好像我什么都没试过，但我试过了.它只是我无法理解的 JSON 部分，Jsfiddle 无法正确读取它.我想知道我的 json 格式是否不正确.任何帮助将不胜感激

The question may sound like i have not tried anything, but i have. its just the JSON part which i cannot understand, Jsfiddle does not read it properly. I am wondering if my jSON is not formatted properly. Any help would be appreciated

推荐答案

只需迭代您的 JSON.menu 数组并从中生成菜单(重命名为 JSON -> data ...):

Just iterate your JSON.menu array and generate the menu from it (renamed JSON -> data ...):

$(function () {
    var getMenuItem = function (itemData) {
        var item = $("<li>")
            .append(
        $("<a>", {
            href: '#' + itemData.link,
            html: itemData.name
        }));
        if (itemData.sub) {
            var subList = $("<ul>");
            $.each(itemData.sub, function () {
                subList.append(getMenuItem(this));
            });
            item.append(subList);
        }
        return item;
    };

    var $menu = $("#menu");
    $.each(data.menu, function () {
        $menu.append(
            getMenuItem(this)
        );
    });
    $menu.menu();
});

http://jsfiddle.net/9uhc3/5/

这篇关于从 JSON 创建菜单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！