如何从列表中查找和替换部分文件名 [英] How to find and replace part of filenames from list

问题描述

我有一个文件列表，我需要在每个文件的同一部分重命名这些文件，并使用不同的值。

I have a list of files that I need to rename at the same part of each file, with different values.

示例：

BL_1402B103_abc.wav > BL_C1234-1_abc.wav

BL_15489B59_abc.wav > BL_C1234-5_abc.wav

因此在上面的第一个示例中，我想替换 1402B103 与 C1234-1 所有文件的长度相同，我要替换的部分用 分隔_ 。

So in the first example above I want to replace the 1402B103 with C1234-1 all the files are the same length and the sections I want to replace are separated by "_".

我有一些代码可用于查找/替换文件名的一部分，但是我需要对数百个文件执行此操作-有没有办法将Pattern =&替换=作为来自csv / list的变量并批量运行？

I have some code for finding/replacing parts of a filename but I need to do this for hundreds of files - is there a way to pull Pattern= & Replace= as variables from a csv/list and run as a batch?

Setlocal enabledelayedexpansion

Set "Pattern=1402B103"
Set "Replace=C1234-1"

For %%f in (*.wav) Do (
    Set "File=%%~f"
    Ren "%%f" "!File:%Pattern%=%Replace%!"
)

推荐答案

您可以创建 csv 文件并添加搜索/替换字符串：

You could create a csv file and add your search/replace strings:

myfile.csv

1402B103,C1234-1
15489B59,C1234-5
etc,etc

批处理文件 myrename.cmd

@echo off
setlocal enabledelayedexpansion
for /f "tokens=1,* delims=," %%i in (myfile.csv) do (
    set "search=%%i"
    set "replace=%%j"
    call :fix
)
exit /b
:fix
    for %%a in (*!search!*.wav) do (
        set "file=%%a"
        set "file=!file:%search%=%replace%!!"
        echo ren "%%~fa" "!file!" 
)

它将坐下对于 csv 文件中的每个字符串，用逗号分隔，将第一个元变量分配给 search 变量，第二个替换变量。然后我们只需调用该过程对每个对象进行替换。

It will seatch for each string in the csv file, split by comma assign the first meta variable to the search variable and the second to the replace variable. Then we simply do the replace for each by calling that procedure.

注意！在这种情况下，我使用了 echo 之前 ren 查看测试结果。只有对结果感到满意后，才能删除 echo 来执行实际的命令。

Note!! in this instance I used echo before ren for testing results. Only once you are happy with your results should you remove echo to perform the actual command.

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