在UNIX中查找作为命令行输入的单词出现的次数 [英] To find number of occurrences of a word taken as input from command line in unix

问题描述

对于文件 file1.txt ，其中包含

Apple fruit Apple tree
Tree AApple AApklle Apple apple
TREE
Apple

我想找到单词 Apple 的出现次数。输出应为 4 。

我的script.sh文件包含

I want to find number of occurrences of the word Apple. Output should be 4.
My script.sh file contains

#!/bin/bash
FILE="$1"
TOFIND="$2"
if [ -f "$FILE" ];
then
grep -o '\<"$TOFIND"\>' "$FILE" | wc -l
fi

当我尝试使用

bash script.sh file1.txt Apple

输出显示 0 。请帮助解决此问题。

The output shows 0. Please help solve this problem.

推荐答案

您可以将grep行更改为：

You can change the grep line to:

grep -o '\<'"$TOFIND"'\>' "$FILE" | wc -l

或仅：

grep -o "\<$TOFIND\>" "$FILE" | wc -l

然后它将起作用。这是因为双引号，双引号都在单引号内引起来，所以它们不会扩展。

Then it will work. It's because the quotes, your double quotes was quoted inside single quotes, so they are not expanded.

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