在 unix 中查找作为输入从命令行输入的单词的出现次数 [英] To find number of occurrences of a word taken as input from command line in unix

问题描述

对于包含

Apple fruit Apple tree
Tree AApple AApklle Apple apple
TREE
Apple

我想找出单词 Apple 出现的次数.输出应该是 4.
我的 script.sh 文件包含

I want to find number of occurrences of the word Apple. Output should be 4.
My script.sh file contains

#!/bin/bash
FILE="$1"
TOFIND="$2"
if [ -f "$FILE" ];
then
grep -o '<"$TOFIND">' "$FILE" | wc -l
fi

当我尝试使用

bash script.sh file1.txt Apple

输出显示 0.请帮忙解决这个问题.

The output shows 0. Please help solve this problem.

推荐答案

您可以将 grep 行更改为:

You can change the grep line to:

grep -o '<'"$TOFIND"'>' "$FILE" | wc -l

或者只是:

grep -o "<$TOFIND>" "$FILE" | wc -l

然后就可以了.这是因为引号，你的双引号是在单引号里面引用的，所以它们没有展开.

Then it will work. It's because the quotes, your double quotes was quoted inside single quotes, so they are not expanded.

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