命令行-int()参数必须是字符串,类似字节的对象或数字,而不是“列表” [英] command line - int() argument must be a string, a bytes-like object or a number, not 'list'
问题描述
我有一个非常基本的代码:
I got a very basic code:
import sys
file = sys.argv[0]
arg = int(sys.argv[1:])
def multiplier(x):
if arg < 1:
print('Put an argument in')
else:
totals = 1
for i in range(1,x+1):
totals *= i
return totals
print(multiplier(arg))
我正在尝试从命令行运行它,并且不断出现此错误:
And I'm trying to run this from the command line and I keep getting this error:
File "program.py", line 4, in <module>
arg = int(sys.argv[1:])
TypeError: int() argument must be a string, a bytes-like object or a
number, not 'list'
我理解该错误,但是我是命令行的新手,所以我对命令行上下文。
I understand the error, but I'm new to the command line so I'm a bit confused in the command line context.
如果一切顺利,我期望这样的东西(输入/输出):
If all went well, I'd expect something like this (Input/output):
>>> Python program.py 10
3628800
如果有人有任何建议,将不胜感激!
If anyone has any suggestions, it would be much appreciated!
推荐答案
方括号中的冒号表示前面的列表对象的一部分。在这种情况下,您只希望第二项(索引为1),而不是列表的一部分 sys.argv
从索引1开始:
A colon in square brackets denotes a slice of the preceding list object. In this case, you want just the second item (with index 1), rather than a slice of the list sys.argv
start from index 1:
arg = int(sys.argv[1])
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