.bat脚本比较两个Windows文件夹的内容 [英] .bat script to compare contents of two windows folders

问题描述

我想编写一个简短的.bat脚本来比较两个文件夹的内容。

I would like to write a short .bat script to compare the contents of two folders.

文件夹1：包含1300个文件。
文件夹2：包含大约400个文件。

Folder 1: Contains some 1300 files. Folder 2: Contains some 400 files.

我想要一个脚本，我可以在Windows命令行中运行该脚本，以对Folder 2中的每个文件进行检查查看文件夹1中是否有相同名称的文件...，如果是，则将文件夹2文件的名称输出为.csv文件（或记事本，我很简单，只需要一个列表！）。

I would like to have a script I can run through the windows command line that takes each file in Folder 2 checks to see if a file with the same name is in Folder 1... and if it is Outputs the name of the Folder 2 file to a .csv file (or notepad I'm easy just want a list!).

任何想法或帮助将不胜感激！

Any thoughts or help would be much appreciated!

推荐答案

尝试一下

(for %%i in ("folder2\*") do if exist "folder1\%%~nxi" echo(%%~i)>file.csv

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