区分日志文件而不考虑时间戳的简单方法？ [英] An easy way to diff log files, ignoring the time stamps?

问题描述

我需要比较两个日志文件，但忽略每行的时间戳部分（准确地说是前12个字符）。

I need to diff two log files but ignore the time stamp part of each line (the first 12 characters to be exact). Is there a good tool, or a clever awk command, that could help me out?

推荐答案

取决于正在使用的shell，是否有一个好的工具或聪明的awk命令可以帮助我？ ，您可以采用 @Blair的方法推荐为1线形

Depending on the shell you are using, you can turn the approach @Blair suggested into a 1-liner

diff <(cut -b13- file1) <(cut -b13- file2)

（+ 1到 @ Blair 作为原始建议：-）

(+1 to @Blair for the original suggestion :-)

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