是否有API方法可以比较Seq的内容而不考虑顺序？ [英] Is there an API method that compares contents of a Seq irrespective of order?

问题描述

假设：

val l1 = List(1,2,3) 
val l2 = List(2,3,1)

我想要一种方法来确认l1等于l2（同上内容，但顺序不同）。列表/序列上是否有API方法可以做到这一点？

I want a method that confirms that l1 is equal to l2 (as in same contents but different order). Is there an API method on List/Seq to do this?

l1.sameElements(l2)

不能正常工作，因为它也可以验证订单。

does not work as it verifies order as well.

我已经提出以下内容：

l1.foldLeft(l1.size == l2.size)(_ && l2.contains(_))

进行上述比较是否比以上更简洁？

Is there anything more succinct than the above to do this comparison?

推荐答案

如果要的是这些列表包含相同的元素，而与顺序或重复无关：

If what you want is "these lists contain the same elements, irrespective of order or repetitions":

l1.toSet == l2.toSet

如果您想要的是这些列表包含相同的元素，并且每个列表具有相同的重复次数：

If what you want is "these lists contain the same elements, and with the same number of repetitions of each":

l1.sorted == l2.sorted

如果您想要的是这些列表包含相同的元素且大小相同，但是给定元素的重复次数在两个列表：

If what you want is "these lists contain the same elements and are the same size, but the number of repetitions of a given element can differ between the two lists":

l1.size == l2.size&& l1.toSet == l2.toSet

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