警告：“整数转换会导致截断” [英] warning : 'integer conversion results in truncation'

问题描述

我在这里得到警告。警告说整数转换会导致截断。即使我删除了typecast（U16），它仍然存在。

I get an warning here. The warning says 'integer conversion results in truncation'. It persists even if I remove the typecast(U16).

typedef unsigned short  U16;
U16 mask;
mask = ~(U16)(0x8000);

如何解决此警告？我使用了下面的代码并删除了警告，但是不确定是否是正确的方法。

How do I resolve this warning? I used the below code and removed the warning, but unsure if its the right way to do it.

mask = (U16)(~(U32)(0x8000));

提前谢谢！

推荐答案

当您尝试将常量值分配给一个不足以容纳它们的L值时，C编译器不喜欢它。我想编译器作者会假设您自声明常量以来就知道应该使用什么值，因此，如果您有可能截断它的值，那一定是错误的。这是一个可行的解决方案，但可能不是您理想的结果：

C compilers don't like when you try to assign constant values into an L-value that's not big enough to hold them. I would guess that the compiler authors assume you know what value should be used since you're declaring a constant, therefore something must be wrong if you're potentially truncating its value. Here's a solution that will work, but may not be your ideal outcome:

typedef unsigned short  U16;
U16 mask;
mask = 0x7fff; //~0x8000;

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