C ++中的临时对象确实是const吗？ [英] Are temporary objects in C++ const indeed?

问题描述

我一直认为C ++中的临时对象会被编译器自动视为const。但是最近我经历了以下代码示例：

I always believed that temporary objects in C++ are automatically considered as const by the compiler. But recently I experienced that the following example of code:


function_returning_object（）。some_non_const_method（）;


对C ++编译器有效。这让我感到奇怪-C ++ const中的临时对象的确是吗？如果是，那么为什么编译器认为上面的代码正确？

is valid for C++ compiler. And it makes me wonder - are temporary objects in C++ const indeed? If yes, then why the code above is considered correct by the compiler?

推荐答案

否，不是。除非您将返回类型声明为const。

No, they're not. Not unless you declare the return type as const.

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