Python计数器单词不是字母 [英] Python counter words not letters

问题描述

我正在尝试创建一个程序，该程序可以读取文本文件并查找单个单词的数量。
我已经解决了大部分问题，但是我坚持要设法让计数器挑选出单词（而不是字母），因为它目前正在这样做。

I'm trying to create a program which reads in a text file and find the number of individual words. I have worked out most of it but I am stuck on trying to get the counter to pick out words not letters as it is currently doing.

import collections 

with open ("file.txt" ,"r") as myfile:
    data=myfile.read()
[i.split(" ") for i in data]

x=collections.Counter(data)

print (x)

我的目标是将列表按空格隔开，这将导致每个单词列表中的一个对象。但是，这没有用。

My aim was to slip the list by whitespace which would result in each word being a object in the list. This however did not work.

结果：

Counter({' ': 1062, 'e': 678, 't': 544, 'o': 448, 'n': 435, 'a': 405, 'i': 401, 'r': 398,       's': 329, 'c': 268, 'm': 230, 'h': 216, 'u': 212, 'd': 190, 'l': 161, 'p': 148, 'f': 107, 'g': 75, 'y': 68, '\n': 65, ',': 61, 'b': 55, 'w': 55, 'v': 55, '.': 53, 'N': 32, 'A': 20, 'T': 19, '"': 18, ')': 17, '(': 17, 'C': 17, 'k': 16, "'": 16, 'I': 16, 'x': 15, '-': 14, 'E': 13, 'q': 12, 'V': 10, 'U': 9, ';': 7, '1': 6, 'j': 5, '4': 5, 'P': 5, 'D': 5, '9': 5, 'L': 4, 'z': 4, 'W': 4, 'O': 3, 'F': 3, '5': 3, 'J': 2, '3': 2, 'S': 2, 'R': 2, '0': 1, ':': 1, 'H': 1, '2': 1, '/': 1, 'B': 1, 'M': 1, '7': 1})

推荐答案

您的列表理解从未分配，因此不会执行任何操作。

Your list comprehension is never assigned and thus doesn't do anything.

将拆分后的文本传递到 collections.Counter（）：

Pass the split text to collections.Counter():

x = collections.Counter(data.split())

我使用了 str.split（）不带参数，以确保您在任意宽度的空格上进行分割，并且在分割时也包括换行符；例如，您的 Counter（）有65个不需要的换行符。

and I used str.split() without arguments to make sure you split on arbitrary width whitespace and include newlines when splitting as well; your Counter() has 65 newlines that need not be there, for example.

在上下文中还有更多内容紧凑：

In context and a little more compact:

from collections import Counter

with open ("file.txt") as myfile:
    x = Counter(myfile.read().split())

print(x)

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