计算句子中的元音数量并显示最频繁的 [英] Count the amount of vowels in a sentence and display the most frequent

问题描述

到目前为止，这是我计算元音的代码。我需要浏览一个句子，计数和比较元音，然后显示出现次数最多的元音。

This is my code so far for counting vowels. I need to to scan through a sentence, count and compare the vowels and then display the top occurring vowels.

from collections import Counter
vowelCounter = Counter()
sentence=input("sentence")
for word in sentence:
    vowelCounter[word] += 1
vowel, vowelCount= Counter(vowel for vowel in sentence.lower() if vowel in "aeiou").most_common(1)[0]

有人有更好的方法吗？

推荐答案

IMO，为避免出现长行，最好避免清晰度：

IMO, long lines are best avoided for the sake of clarity:

#!/usr/local/cpython-3.3/bin/python

import collections

sentence = input("sentence").lower()
vowels = (c for c in sentence if c in "aeiou")
counter = collections.Counter(vowels)
most_common = counter.most_common(1)[0]
print(most_common)

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