显示具有最小给定元音数量的文件中的单词 [英] Show words from a file with a minimum given number of vowels

问题描述

我正在尝试解决问题，但不知道如何解决。
问题是，给定一个输入文件，该文件的第一行具有数字k，第二行具有一些单词，K是必须在控制台中打印一个单词的最小元音数量。 / p>

I'm trying to solve a problem and i can't figure out how to do it. The problem says that given an input file which has on the first line a number k and on the next lines some words, K is the minimum number of vowels that a word needs to have to be printed in the console.

Example:
Input: test.in
cars
are...great and awesome

Output:
If k is 2 the result should be:
are
great
awesome
And also it should not take into account spaces or other characters like .,!,? and so on.

到目前为止我所拥有的：

What i have so far:

 int main(){

    ifstream fin("dataTest.in");
    char s[250];
    int k;
    fin>>k;
    int nrVowels=0;

    while(fin>>s) {

         int n = strlen(s);

            for(int i=0; i < n; i++)

            {
                    if (s[i] == 'a' ||  s[i] == 'e' ||  s[i] == 'o' ||  s[i] == 'i' || s[i] == 'u'){
                        nrVowels++;
                        if(nrVowels == k){
                            cout<<"Here i guess i should print the word?";
                        }
                    }
            }
    }

}

正如您从代码中看到的那样，我的问题是我不确定我应该如何打印单词以及如何知道单词的结尾，因为我不想只打印这个词的一部分。
你们对我应该怎么做有任何想法吗？

As you can see from the code my problem is that i'm not really sure how i should print the word and how would i know where the word is ending because i don't want to print only a part of the word. Do you guys have any ideas on how i should do this?

推荐答案

std::ifstream file("Read.txt");
int number;
file>>number;
std::string str; 
auto vowels = [](char c){return c == 'a' ||  c == 'e' ||  c  == 'o' ||  c  == 'i' || c  == 'u';};
while (std::getline(file, str))
{
    if(std::count_if(str.cbegin(), str.cend(), vowels) >= number){
        std::cout<<str<<'\n';
    }
}

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