C ++ STL cout源代码 [英] c++ STL cout source code

问题描述

我想查看STL std :: cout 函数的源代码。我查看了iostream，但只看到了外部提示。因此，我想它是在库中定义的。

I want to see source code of STL std::cout function. I looked at iostream, but I've seen only "extern cout". So, I guess that it's defined somewhere in the library.

我从官方网站

我将其提取并做了：

sh@sh-R528-R728:~/desktop/stl$ grep -F * | grep "cout"

但我什么也没得到。

我在做什么错？源代码在哪里？

What am I doing wrong? Where is the source code?

推荐答案

cout 不属于STL，因此您不会在STL源中找到 cout 的源。

cout is not part of the STL, so you won't find the source for cout in the STL source.

您可能想看看C ++标准库的源代码，该库基于STL，但还包含iostream。这取决于您使用的平台。

You probably want to look for the source for your C++ standard library, which was based on the STL, but also contains iostreams. Where that is depends on what platform you're using.

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