输出包含所有转义字符的C ++字符串 [英] Output a C++ string including all escape characters

问题描述

我有一个像这样的字符串：

I have a string like this:

string s = "\t Hello \n";

打印时，它会给我一个选项卡，然后是Hello，然后是新行。但是，无论如何我都可以打印出来，以便在控制台中看到它：

When I print it then it gives me a tab then Hello then a new line. However, is there anyway I can print it such that I see this in my console:

\t Hello \n

换句话说，我希望字符串忽略转义字符并将其视为实际字符串？ / p>

In other words, I want the string to disregard the escape characters and treat it as an actual string?

推荐答案

换句话说，我希望字符串忽略转义字符并将其视为实际字符

In other words, I want the string to disregard the escape characters and treat it as an actual string?

如所示，如果字符串是硬编码的，则可以对其进行修改以使用：

If the string is hard coded, as you show, you can modify it to use:

string s = "\\t Hello \\n";

如果您希望能够处理程序中抛出的任何字符串，则必须编写

If you want to be able to handle any string thrown at your program, you'll have to write a function and deal with all the escape sequences allowed by the language.

std::ostream& writeString(std::ostream& out, std::string const& s)
{
   for ( auto ch : s )
   {
      switch (ch)
      {
         case '\'':
            out << "\\'";
            break;

         case '\"':
            out << "\\\"";
            break;

         case '\?':
            out << "\\?";
            break;

         case '\\':
            out << "\\\\";
            break;

         case '\a':
            out << "\\a";
            break;

         case '\b':
            out << "\\b";
            break;

         case '\f':
            out << "\\f";
            break;

         case '\n':
            out << "\\n";
            break;

         case '\r':
            out << "\\r";
            break;

         case '\t':
            out << "\\t";
            break;

         case '\v':
            out << "\\v";
            break;

         default:
            out << ch;
      }
   }

   return out;
}

用作：

writeString(std::cout, s);

这篇关于输出包含所有转义字符的C ++字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！