在x86 Assembly中分割64位的问题 [英] Problems dividing 64 bits in x86 Assembly

问题描述

在x86 Assembly中分割时，我不断收到程序收到信号SIGFPE，算术异常。这很令人困惑，因为如果我除以10，答案应该小于64位答案。...

  mov $ 0x82b40000， $ eax 
 mov $ 0x21c3677c，$ edx 
 mov $ 10000000，％ebx 
 div％ebx 
  

解决方案

算术异常为整数溢出，来自 #DE 硬件除法异常！
这是正常现象或预期结果，因为结果大于32位数字。

请记住：64位/ 32位除法的商只是一个32位寄存器（EAX）。 EDX输出是余数，不是商的一半。 div％ebx 的操作数大小为32位；

英特尔的数据表中有一个有用的表：

I keep getting 'Program received signal SIGFPE, Arithmetic exception' when dividing in x86 Assembly. It's confusing because the answer should be smaller than a 64 bit answer if I divide by 10....

mov $0x82b40000, $eax
mov $0x21c3677c, $edx
mov $10000000, %ebx
div %ebx

解决方案

The arithmetic exception is "Integer overflow", from the #DE hardware divide exception! Which is normal or expected, because your result is bigger than 32-bit number.

Remember: the quotient of 64 bit / 32-bit division is only a 32 bit register (EAX). The EDX output is the remainder, not high half of the quotient. The operand-size of div %ebx is 32-bit; only the dividend is 64-bit.

Intel's datasheet has a useful table:

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