如何查找某个目录中包含最多文件的子目录 [英] How to find subdirectory of some directory, which have most files

问题描述

我已经使用 bash 完成了操作，但是如何使用 tcsh 获取此子目录的名称或路径。稍后我需要计算该子目录中所有文件的总大小，请帮助我。

I have already done it using bash, but how can i get name or path to this subdirectory using tcsh. Later i need to count total size of all files in this subdirectory, please help me.

例如：

someDirectory

--firstDirectory

---- file11.txt

---- file12.txt

---- file13.txt

- secondDirectory

---- file21.txt

--thirdDirectory

---- file31.txt

---- file32.txt

---- file33.txt

---- file34.txt

---- file35 .txt

someDirectory
--firstDirectory
----file11.txt
----file12.txt
----file13.txt
--secondDirectory
----file21.txt
--thirdDirectory
----file31.txt
----file32.txt
----file33.txt
----file34.txt
----file35.txt

结果，我想获取ThirdDirectory的路径，因为它包含的文件最多。

And as result i want to get path to the thirdDirectory, cause it have most files.

更新

解决方案

#!/bin/bash -f 

declare -i maxcount=0
declare -i count
declare maxdirectory

find someFolder -type d | while read DIR;
    do let count=`(ls $DIR | wc -w)`
    if(($count > $maxcount)); then 
        let maxcount=count 
        maxdirectory="$DIR"
    fi 
done

更新

Tcsh解决方案

cd $1
foreach x(*)
    if(-d $x) then
    set count = `(ls $x -1 | wc -l)`
        if($count > $maxcount) then
            set directory = $x
            set maxcount = $count
        endif
    endif
end

推荐答案

您可以使用cut：

find . | rev | cut -d "/" -f2- | rev | sort | uniq -c | sort -k1n,1 | tail -n1

或awk：

find . | awk -F "/" '{for(i=1;i<=NF-1;i++) printf $i"/"; printf "\n"}' | sort | uniq -c | sort -k1n,1 | tail -n1

您可以使用的已识别目录中的文件大小：

The file size in the identified directory you can get with:

du -s

或：

ls -lh | head -n1

有人问了类似的问题，但不幸的是它已关闭：在Linux中，如何找到包含最多子目录或文件的目录？

Somebody asked a similar question, but unfortunately it was closed: In Linux, how do I find find directory with the most subdirectories or files?

如果只想计算文件而不是目录，则添加-type f以查找。

Add -type f to find, if you only want to count files and not directories.

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